Integrand size = 31, antiderivative size = 401 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx=-\frac {2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt {a+b \sin (c+d x)}}+\frac {8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^5 d}-\frac {16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^4 d}+\frac {2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt {a+b \sin (c+d x)}}{63 a b^3 d}-\frac {2 \cos (c+d x) \sin ^3(c+d x) \sqrt {a+b \sin (c+d x)}}{9 b^2 d}+\frac {8 \left (320 a^4-318 a^2 b^2+21 b^4\right ) E\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {a+b \sin (c+d x)}}{315 b^6 d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {16 a \left (160 a^4-199 a^2 b^2+39 b^4\right ) \operatorname {EllipticF}\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right ),\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{315 b^6 d \sqrt {a+b \sin (c+d x)}} \]
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Time = 0.65 (sec) , antiderivative size = 401, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.258, Rules used = {2971, 3128, 3102, 2831, 2742, 2740, 2734, 2732} \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx=-\frac {2 \left (a^2-b^2\right ) \sin ^3(c+d x) \cos (c+d x)}{a b^2 d \sqrt {a+b \sin (c+d x)}}+\frac {8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^5 d}-\frac {16 \left (60 a^2-49 b^2\right ) \sin (c+d x) \cos (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^4 d}+\frac {2 \left (80 a^2-63 b^2\right ) \sin ^2(c+d x) \cos (c+d x) \sqrt {a+b \sin (c+d x)}}{63 a b^3 d}-\frac {16 a \left (160 a^4-199 a^2 b^2+39 b^4\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} \operatorname {EllipticF}\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right ),\frac {2 b}{a+b}\right )}{315 b^6 d \sqrt {a+b \sin (c+d x)}}+\frac {8 \left (320 a^4-318 a^2 b^2+21 b^4\right ) \sqrt {a+b \sin (c+d x)} E\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{315 b^6 d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {2 \sin ^3(c+d x) \cos (c+d x) \sqrt {a+b \sin (c+d x)}}{9 b^2 d} \]
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Rule 2732
Rule 2734
Rule 2740
Rule 2742
Rule 2831
Rule 2971
Rule 3102
Rule 3128
Rubi steps \begin{align*} \text {integral}& = -\frac {2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt {a+b \sin (c+d x)}}-\frac {2 \cos (c+d x) \sin ^3(c+d x) \sqrt {a+b \sin (c+d x)}}{9 b^2 d}+\frac {4 \int \frac {\sin ^2(c+d x) \left (\frac {15}{4} \left (4 a^2-3 b^2\right )-\frac {1}{2} a b \sin (c+d x)-\frac {1}{4} \left (80 a^2-63 b^2\right ) \sin ^2(c+d x)\right )}{\sqrt {a+b \sin (c+d x)}} \, dx}{9 a b^2} \\ & = -\frac {2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt {a+b \sin (c+d x)}}+\frac {2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt {a+b \sin (c+d x)}}{63 a b^3 d}-\frac {2 \cos (c+d x) \sin ^3(c+d x) \sqrt {a+b \sin (c+d x)}}{9 b^2 d}+\frac {8 \int \frac {\sin (c+d x) \left (-\frac {1}{2} a \left (80 a^2-63 b^2\right )+\frac {5}{2} a^2 b \sin (c+d x)+a \left (60 a^2-49 b^2\right ) \sin ^2(c+d x)\right )}{\sqrt {a+b \sin (c+d x)}} \, dx}{63 a b^3} \\ & = -\frac {2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt {a+b \sin (c+d x)}}-\frac {16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^4 d}+\frac {2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt {a+b \sin (c+d x)}}{63 a b^3 d}-\frac {2 \cos (c+d x) \sin ^3(c+d x) \sqrt {a+b \sin (c+d x)}}{9 b^2 d}+\frac {16 \int \frac {a^2 \left (60 a^2-49 b^2\right )-\frac {1}{4} a b \left (40 a^2-21 b^2\right ) \sin (c+d x)-\frac {3}{4} a^2 \left (160 a^2-139 b^2\right ) \sin ^2(c+d x)}{\sqrt {a+b \sin (c+d x)}} \, dx}{315 a b^4} \\ & = -\frac {2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt {a+b \sin (c+d x)}}+\frac {8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^5 d}-\frac {16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^4 d}+\frac {2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt {a+b \sin (c+d x)}}{63 a b^3 d}-\frac {2 \cos (c+d x) \sin ^3(c+d x) \sqrt {a+b \sin (c+d x)}}{9 b^2 d}+\frac {32 \int \frac {\frac {3}{8} a^2 b \left (80 a^2-57 b^2\right )+\frac {3}{8} a \left (320 a^4-318 a^2 b^2+21 b^4\right ) \sin (c+d x)}{\sqrt {a+b \sin (c+d x)}} \, dx}{945 a b^5} \\ & = -\frac {2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt {a+b \sin (c+d x)}}+\frac {8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^5 d}-\frac {16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^4 d}+\frac {2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt {a+b \sin (c+d x)}}{63 a b^3 d}-\frac {2 \cos (c+d x) \sin ^3(c+d x) \sqrt {a+b \sin (c+d x)}}{9 b^2 d}+\frac {\left (4 \left (320 a^4-318 a^2 b^2+21 b^4\right )\right ) \int \sqrt {a+b \sin (c+d x)} \, dx}{315 b^6}-\frac {\left (8 a \left (160 a^4-199 a^2 b^2+39 b^4\right )\right ) \int \frac {1}{\sqrt {a+b \sin (c+d x)}} \, dx}{315 b^6} \\ & = -\frac {2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt {a+b \sin (c+d x)}}+\frac {8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^5 d}-\frac {16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^4 d}+\frac {2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt {a+b \sin (c+d x)}}{63 a b^3 d}-\frac {2 \cos (c+d x) \sin ^3(c+d x) \sqrt {a+b \sin (c+d x)}}{9 b^2 d}+\frac {\left (4 \left (320 a^4-318 a^2 b^2+21 b^4\right ) \sqrt {a+b \sin (c+d x)}\right ) \int \sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}} \, dx}{315 b^6 \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {\left (8 a \left (160 a^4-199 a^2 b^2+39 b^4\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}\right ) \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}}} \, dx}{315 b^6 \sqrt {a+b \sin (c+d x)}} \\ & = -\frac {2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt {a+b \sin (c+d x)}}+\frac {8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^5 d}-\frac {16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt {a+b \sin (c+d x)}}{315 b^4 d}+\frac {2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt {a+b \sin (c+d x)}}{63 a b^3 d}-\frac {2 \cos (c+d x) \sin ^3(c+d x) \sqrt {a+b \sin (c+d x)}}{9 b^2 d}+\frac {8 \left (320 a^4-318 a^2 b^2+21 b^4\right ) E\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {a+b \sin (c+d x)}}{315 b^6 d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {16 a \left (160 a^4-199 a^2 b^2+39 b^4\right ) \operatorname {EllipticF}\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right ),\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{315 b^6 d \sqrt {a+b \sin (c+d x)}} \\ \end{align*}
Time = 3.94 (sec) , antiderivative size = 275, normalized size of antiderivative = 0.69 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx=\frac {-32 \left (320 a^5+320 a^4 b-318 a^3 b^2-318 a^2 b^3+21 a b^4+21 b^5\right ) E\left (\frac {1}{4} (-2 c+\pi -2 d x)|\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}+64 a \left (160 a^4-199 a^2 b^2+39 b^4\right ) \operatorname {EllipticF}\left (\frac {1}{4} (-2 c+\pi -2 d x),\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}-b \cos (c+d x) \left (-5120 a^4+4768 a^2 b^2-203 b^4-8 \left (40 a^2 b^2-21 b^4\right ) \cos (2 (c+d x))+35 b^4 \cos (4 (c+d x))-1280 a^3 b \sin (c+d x)+1012 a b^3 \sin (c+d x)+100 a b^3 \sin (3 (c+d x))\right )}{1260 b^6 d \sqrt {a+b \sin (c+d x)}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(1189\) vs. \(2(437)=874\).
Time = 2.50 (sec) , antiderivative size = 1190, normalized size of antiderivative = 2.97
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.22 (sec) , antiderivative size = 723, normalized size of antiderivative = 1.80 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx=-\frac {2 \, {\left (2 \, {\left (\sqrt {2} {\left (640 \, a^{5} b - 876 \, a^{3} b^{3} + 213 \, a b^{5}\right )} \sin \left (d x + c\right ) + \sqrt {2} {\left (640 \, a^{6} - 876 \, a^{4} b^{2} + 213 \, a^{2} b^{4}\right )}\right )} \sqrt {i \, b} {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (8 i \, a^{3} - 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) - 3 i \, b \sin \left (d x + c\right ) - 2 i \, a}{3 \, b}\right ) + 2 \, {\left (\sqrt {2} {\left (640 \, a^{5} b - 876 \, a^{3} b^{3} + 213 \, a b^{5}\right )} \sin \left (d x + c\right ) + \sqrt {2} {\left (640 \, a^{6} - 876 \, a^{4} b^{2} + 213 \, a^{2} b^{4}\right )}\right )} \sqrt {-i \, b} {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (-8 i \, a^{3} + 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) + 3 i \, b \sin \left (d x + c\right ) + 2 i \, a}{3 \, b}\right ) + 6 \, {\left (\sqrt {2} {\left (320 i \, a^{4} b^{2} - 318 i \, a^{2} b^{4} + 21 i \, b^{6}\right )} \sin \left (d x + c\right ) + \sqrt {2} {\left (320 i \, a^{5} b - 318 i \, a^{3} b^{3} + 21 i \, a b^{5}\right )}\right )} \sqrt {i \, b} {\rm weierstrassZeta}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (8 i \, a^{3} - 9 i \, a b^{2}\right )}}{27 \, b^{3}}, {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (8 i \, a^{3} - 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) - 3 i \, b \sin \left (d x + c\right ) - 2 i \, a}{3 \, b}\right )\right ) + 6 \, {\left (\sqrt {2} {\left (-320 i \, a^{4} b^{2} + 318 i \, a^{2} b^{4} - 21 i \, b^{6}\right )} \sin \left (d x + c\right ) + \sqrt {2} {\left (-320 i \, a^{5} b + 318 i \, a^{3} b^{3} - 21 i \, a b^{5}\right )}\right )} \sqrt {-i \, b} {\rm weierstrassZeta}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (-8 i \, a^{3} + 9 i \, a b^{2}\right )}}{27 \, b^{3}}, {\rm weierstrassPInverse}\left (-\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2}\right )}}{3 \, b^{2}}, -\frac {8 \, {\left (-8 i \, a^{3} + 9 i \, a b^{2}\right )}}{27 \, b^{3}}, \frac {3 \, b \cos \left (d x + c\right ) + 3 i \, b \sin \left (d x + c\right ) + 2 i \, a}{3 \, b}\right )\right ) + 3 \, {\left (35 \, b^{6} \cos \left (d x + c\right )^{5} - {\left (80 \, a^{2} b^{4} - 7 \, b^{6}\right )} \cos \left (d x + c\right )^{3} - 2 \, {\left (320 \, a^{4} b^{2} - 318 \, a^{2} b^{4} + 21 \, b^{6}\right )} \cos \left (d x + c\right ) + 2 \, {\left (25 \, a b^{5} \cos \left (d x + c\right )^{3} - {\left (80 \, a^{3} b^{3} - 57 \, a b^{5}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )\right )} \sqrt {b \sin \left (d x + c\right ) + a}\right )}}{945 \, {\left (b^{8} d \sin \left (d x + c\right ) + a b^{7} d\right )}} \]
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Timed out. \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx=\text {Timed out} \]
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\[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx=\int { \frac {\cos \left (d x + c\right )^{4} \sin \left (d x + c\right )^{2}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{\frac {3}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx=\int \frac {{\cos \left (c+d\,x\right )}^4\,{\sin \left (c+d\,x\right )}^2}{{\left (a+b\,\sin \left (c+d\,x\right )\right )}^{3/2}} \,d x \]
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